int posix_memalign(void **memptr, size_talignment,
size_tsize);
DESCRIPTION
The posix_memalign() function shall allocate size bytes
aligned on a boundary specified by alignment, and
shall return a pointer to the allocated memory in memptr. The
value of alignment shall be a multiple of
sizeof( void *), that is also a power of two. Upon successful
completion, the value pointed to by memptr shall
be a multiple of alignment.
The
free() function shall deallocate memory that has previously
been allocated by
posix_memalign().
RETURN VALUE
Upon successful completion, posix_memalign() shall return zero;
otherwise, an error number shall be returned to indicate
the error.
ERRORS
The posix_memalign() function shall fail if:
EINVAL
The value of the alignment parameter is not a power of two multiple
of sizeof( void *).
ENOMEM
There is insufficient memory available with the requested alignment.
The following sections are informative.
EXAMPLES
None.
APPLICATION USAGE
The posix_memalign() function is part of the Advisory Information
option and need not be provided on all
implementations.
RATIONALE
None.
FUTURE DIRECTIONS
None.
SEE ALSO
free() , malloc() , the Base Definitions volume of
IEEE Std 1003.1-2001, <stdlib.h>
COPYRIGHT
Portions of this text are reprinted and reproduced in electronic form
from IEEE Std 1003.1, 2003 Edition, Standard for Information Technology
-- Portable Operating System Interface (POSIX), The Open Group Base
Specifications Issue 6, Copyright (C) 2001-2003 by the Institute of
Electrical and Electronics Engineers, Inc and The Open Group. In the
event of any discrepancy between this version and the original IEEE and
The Open Group Standard, the original IEEE and The Open Group Standard
is the referee document. The original Standard can be obtained online at
http://www.opengroup.org/unix/online.html .
